When 1 is entered, The output of the code below is?
#include
void main()
{
int ch;
printf("enter a value btw 1 to 2:");
scanf("%d", &ch);
switch (ch, ch + 1)
{
case 1:
printf("1\n");
break;
case 2:
printf("2");
break;
}
}
Answer: B
No answer description available for this question.
When 2 is entered, The output of the code below is?
#include
void main()
{
int ch;
printf("enter a value btw 1 to 2:");
scanf("%d", &ch);
switch (ch)
{
case 1:
printf("1\n");
break;
printf("Hi");
default:
printf("2\n");
}
}
Answer: D
No answer description available for this question.
When 1 is entered, The output of the code below is?
#include
void main()
{
int ch;
printf("enter a value btw 1 to 2:");
scanf("%d", &ch);
switch (ch)
{
case 1:
printf("1\n");
default:
printf("2\n");
}
}
Answer: C
No answer description available for this question.
The output of the code below is
#include
void main()
{
char *ch;
printf("enter a value btw 1 to 3:");
scanf("%s", ch);
switch (ch)
{
case "1":
printf("1");
break;
case "2":
printf("2");
break;
}
}
Answer: C
No answer description available for this question.
The output of the code below is
#include
void main()
{
double ch;
printf("enter a value btw 1 to 2:");
scanf("%lf", &ch);
switch (ch)
{
case 1:
printf("1");
break;
case 2:
printf("2");
break;
}
}
Answer: A
No answer description available for this question.